 25 July 2019 AD; St James the Greater; St Christopher

"Give me an experimental angle from Quantum Mechanics and I will calculate its value exactly."

All the spherical sums of the angles for quarks, neutrinos, bosons, and gravitons, when multiplied by a unique fraction (more in next article), should give CP Violation Phase angle, which is for quarks calculated at δ = 68.755 deg +/- 4.5837deg, and they do indeed give this result.

*It is quite possible that the CP Violation Phase for Graviton is different than for Quark, even if the sum of all the angles are almost the same.

The calculation for quark.

First, in spherical geometry - the sum of all six quark mixing angles (three mixing angles and three final mixing angles) is: 90.4706 deg

The fraction to multiply the above value to get a result close to CP Violation Phase = δ = 68.755 deg is ( 4 / 21 )

Here is the "procedure":

[ 90.4706 deg + 3 * ( 90.4706 deg ) ] * ( 4 / 21 ) = 361. 8824 deg * ( 4 / 21 ) = 68. 9230 deg (spherical)

Now, we have to transform this spherical value into regular "flat" geometry:

The correction coefficient , ε is:

ε = ( 0.4706 deg ) / ( 90.4706 deg ) = 5.2017 X 10-3

In degrees, the correction is:

68.9230 deg * ε = 0.3585 deg

Now, "flat" angle equals to

68.9230 deg - 0.3585 deg = 68.5644 deg ("flat")

The angle inbetween spherical and regular geometry is average of those two terms:

( 68.9230 deg + 68.5644 deg ) / 2 = 68.7437 deg (ave)

The same fraction ) 4 / 21 ) is applied to the graviton to get the spherical angle, regular angle, and the angle in between, a mix of spherical and flat geometry.

The calculation of a spherical value of CP Violation Phase Angle for Graviton :

(This result for Graviton will be tested later on, I can tell you now, that CP Violation Phase Angle of Graviton is different than that of Quark).

[ 90.5494 deg + 3 * ( 90.5494 deg ) ] 8 ( 4 / 21 ) = 362.1976 deg * ( 4 / 21 ) = 68.9900 deg (spherical)

Correction factor, epsilon, to get back to flat geometry:

ε = ( 0.5494 deg / 90.5494 deg ) = 6.0674X10-3 deg

Flat value of the CP Angle is:

68.9900 deg - 6.0674X10-3 * 68.9900 deg = 68.5714 deg (flat)

Average between those two values is:

[ 68.9900 deg + 68.5714 deg ] / 2 = 68.7807 deg (ave)

The quark and graviton together:

Spherical value of CP Angle:

(90.4706 deg + 90.5494 deg = 181.0200 deg

[ 181.0200 deg + 181.0200 deg ] * ( 4 / 21 ) = 68.9600 deg (spherical)

The transformation to flat geometry:

The correction factor, epsilon

ε = 1.0200 deg / 181.0200 deg = 5.6347 X 10-3

68.9600 deg - ( ε ) * (68.9600 deg ) = 68.5714 deg (flat)

Average between spherical and flat geometries :

ave = 68.7657 deg (ave)

So, the final results are:

Quark δ = 68.7437 deg (ave)

Graviton δ = 68.7807 deg (ave)

Quark and Graviton together δ = 68.7657 deg (ave)

If we take the average of Quark and (Quark and graviton together) then the average isδ = 68.7547 deg

Official value is 68.755 deg but with only one decimal place of accuracy, i.e. δ = 68.7 deg

Before proceeding to other properties of CP Violation phase for quark and neutrino, in the next article I post some rules for those "Quantum Fractions".

Comments powered by CComment